Saturday, November 26, 2016

10x faster than Delegate.DynamicInvoke

This is a follow up to my previous blog posts, Optimizing Dynamic Method Invokes in .NET, and Dynamically Invoke Methods Quickly, with InvokeHelpers.EfficientInvoke. Basically, I have re-implemented this for Tact.NET in a way that makes it smaller, faster, and compatible with the .NET Standard.

So, how much faster is this new way of doing things? EfficientInvoker.Invoke is over 10x faster than Delegate.DynamicInvoke, and 10x faster than MethodInfo.Invoke.

Check out the source on GitHub:

Simple Explanation

Here is an example of a method and a class that we might want to invoke dynamically...

public class Tester
{
    public bool AreEqual(int a, int b)
    {
        return a == b;
    }
}

...and then here is the code that the EfficientInvoker will generate at runtime to call that method:

public static object GeneratedFunction(object target, object[] args)
{
    return (object)((Tester)target).AreEqual((int)args[0], (int)args[1]);
}

See, it's simple!

Sample Tests

public class EfficientInvokerTest
{
    public void DelegateInvoke()
    {
        var del = (Delegate) new Func<int, int, bool>((a, b) => a == b);
            
        // Standard slow way
        var result1 = (bool)del.DynamicInvoke(1, 2);
        Assert.False(result1);
 
        // New 10x faster way
        var invoker = del.GetInvoker();
        var result2 = (bool)invoker.Invoke(del, 1, 2);
        Assert.False(result2);
    }
    
    public void MethodInvoke()
    {
        var tester = new Tester();
        var type = tester.GetType();
 
        // Standard slow way
        var methodInfo = type.GetTypeInfo().GetMethod("AreEqual");
        var result1 = (bool) methodInfo.Invoke(tester, new object[] {1, 2});
        Assert.False(result1);
 
        // New 10x faster way
        var invoker = type.GetMethodInvoker("AreEqual");
        var result2 = (bool) invoker.Invoke(tester, 1, 2);
        Assert.False(result2);
    }
    
    private class Tester
    {
        public bool AreEqual(int a, int b)
        {
            return a == b;
        }
    }
}

Enjoy,
Tom

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